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Find n in a sequence

Find nn: which term, how many terms, least nn

  • In 16 of 20 recent exams
  • 2% of the marks
  • Paper 1 or 2
  • 2 to 6 marks
How it is set in the exam

Paper 1 (no calculator) or Paper 2 (calculator), 2–6 marks, often the last part of a context question

Spot it in the exam
First, split

"== value" (which row has 50 seats? how many rows hold 1050 seats?) → an equation, and nn must come out a whole number. ">> value", "exceeds", "less than" → an inequality, and you round in the direction the question needs: least nn → up; greatest nn / the most that fit → down.

Exam phrases to spot (6)
  • “find which term…”

  • “how many terms…”

  • “find the least value of nn for which…”

  • “the smallest number of terms”

  • “in which year does … first exceed…”

  • “the greatest number of rows that can be built”

In disguise (9)
  • "how many terms must be added for the total to exceed…"
  • "the first term that is negative" (asks for nn or for the term's value: read which)
  • "the most rows that fit", "how many terms are less than 500": a greatest nn, so round down
  • "the maximum value of SnS_n" for a decreasing arithmetic sequence: the sum peaks at the last positive term, where the terms reach zero
  • "within 0.001 of the sum to infinity": S∞−Sn<0.001S_\infty - S_n < 0.001
  • "after how many complete years is it worth less than half…", "how long until the investment doubles" (compound interest with the time unknown)
  • "the first month in which Ben's savings overtake Anna's"
  • rows of equal shapes stacked until they pass a given height: each row adds the same height, such as the height of an equilateral triangle of side ss, 32s\frac{\sqrt{3}}{2}s (Right-angled triangles and exact values), so the least number of rows comes from an inequality in nn
  • the least nn for which a running total fills whole boxes with none spare (say SnS_n divisible by 1212): no equation or inequality gives it, so list SnS_n in a table and take the first nn that works

A sigma with an unknown top limit (see Sigma notation) is solved the same way, but it stays in Sigma notation, because decoding the sigma is the hard part.

Looks like it, but isn't (6)
  • "show that the total never reaches…": no nn works, so nothing is found for nn. The proof is the sum to infinity: Sum to infinity, and when it exists
  • an exponential equation with nothing to count (no terms, periods or whole years), such as 2x+1=72^{x+1} = 7: Solve an exponential equation (unknown in the power, or in the base)
  • a formula in continuous time, such as N0×1.035tN_0 \times 1.035^t or 500e−0.04t500e^{-0.04t}, even when a whole number of units or a calendar year is asked: Exponential and log models (solve for tt, then round to the unit asked
  • the number of trials is fixed and the probability of at least one success is asked: 1−P(none)1 - \mathrm{P}(\text{none}), with no unknown nn (Tree diagrams and repeated draws)
  • the least number of trials for at least k≥2k \ge 2 successes, each trial with the same probability: no formula to solve, so tabulate P(X≥k)=1−P(X≤k−1)\mathrm{P}(X \ge k) = 1 - \mathrm{P}(X \le k - 1) against nn: Binomial probabilities: recognise B(n, p), then translate the words (for at least one, 1−(1−p)n1 - (1 - p)^n stays here)
  • a least number of games, items or tickets for an expected total to reach a target: Expected value in context: fair games, totals and the least number. The inequality is linear, n E(X)−fixed cost≥targetn\,\mathrm{E}(X) - \text{fixed cost} \ge \text{target}, and the round-up rule here finishes it
Worked example

Equations: which row, how many rows

Paper 1 (no calculator)
Question

The first row of a theatre has 1818 seats, and each row has 22 more seats than the row in front of it.
(a) Find which row has 5050 seats. [2]
(b) The theatre has 10501050 seats in total. Find the number of rows. [4]

Try it yourself first, then compare.

Now try one like it

Write your working on paper or on screen. Paper Zero marks it step by step, like the worked example, and shows where each mark went. Free, with no account.

A handwritten page as Paper Zero marks it: ticks at the two lines that earned a mark, a cross on line 3 where +7 was copied as −7, and a short note beside that line.123456f′(x) = 4x − 124x − 12 = 0, so x = 3f(3) = 2(3)² − 12(3) − 7= 18 − 36 − 7 = −25minimum at (3, −25)M1 ✓A1 ✓A1 ✗11The +7 became −7: 18 − 36 + 7 = −11.
See it move: Which row, how many rows
  • Sn=800S_n = 800 gives n=21.03n = 21.03, not a whole number. S21=798<800S_{21} = 798 < 800 and S22=858>800S_{22} = 858 > 800: the least nn with Sn>800S_n > 800 is 22, and the most rows with at most 800 seats is 21.
  • Each bar is a row: row nn has un=18+2(n−1)u_n = 18 + 2(n - 1) seats, and the first nn rows hold Sn=n2(36+2(n−1))=n2+17nS_n = \frac{n}{2}(36 + 2(n - 1)) = n^{2} + 17n seats. A total is SnS_n, not unu_n.
  • (b) 1050 seats in total: n(n+17)=1050n(n + 17) = 1050, so (n+42)(n−25)=0(n + 42)(n - 25) = 0. n=−42n = -42 is impossible for a number of rows: 25 rows. Check: u25=66u_{25} = 66 and 252(18+66)=1050\frac{25}{2}(18 + 66) = 1050.
  • "== a value" is an equation, and nn must come out whole. "Exceeds", "more than" or "the most that fit" is an inequality: a least nn rounds up, a greatest nn rounds down, and you show the whole numbers either side, one short and the next over.
Which method?
  • arithmetic term
    linear inequality
    same
  • arithmetic sum, or two arithmetic sums compared
    quadratic inequality, using n>0n > 0
    table, or solve and round (step 4)
  • geometric term or sum
    isolate rnr^n and compare with powers (210=10242^{10} = 1024, 35=2433^5 = 243); logs if asked, flipping the sign for 0<r<10 < r < 1
    table, or solve and round (step 4)
  • arithmetic against geometric
    not set
    table only

An equation ("== value") is solved directly: linear for an arithmetic term, a quadratic for an arithmetic sum (reject the negative root), powers for geometric.

Steps
  1. Write the quantity in nn: unu_n, SnS_n, S∞−SnS_\infty - S_n, or the difference of two sums.

  2. Write the equation or inequality with the correct sign ("exceeds" is strict, >>). Solving the equation (==) instead of the inequality is accepted; an inequality the wrong way round loses the set-up mark ( in some markschemes, in others).

  3. Solve by the method in the table.

  4. For an inequality, round in the direction the question needs: least nn → up; greatest nn / the most that fit → down. Then show the two whole numbers either side: one fails and the next works (for a least nn), or one works and the next fails (for a greatest nn).

  5. Answer what was asked: nn, the term's value, or the calendar year.

Common mistakes
  • Not reversing the inequality

    after dividing by ln⁡r\ln r with 0<r<10 < r < 1.

  • Rounding the wrong way.

    A least nn rounds up: n>27.6n > 27.6 means n=28n = 28. A greatest nn rounds down: n<125.25n < 125.25 means n=125n = 125. Ask which one the question wants before rounding.

  • An inequality the wrong way round

    writing Sn<120S_n < 120 for "exceeds 120" loses the set-up mark ( in some markschemes, in others), even if the final nn happens to be right. Writing the equation Sn=120S_n = 120 instead is accepted for that mark.

More mistakes (6)
  • Missing the strict inequality

    if S10=120S_{10} = 120 exactly, then "exceeds 120" needs n=11n = 11.

  • "Never reaches" shown with a few sums

    calculate S∞S_\infty and compare it with the target.

  • nn against n−1n - 1 in the power

    unu_n uses rn−1r^{n-1}, and SnS_n uses rnr^n.

  • Giving the answer as a decimal

    (n=29.65n = 29.65). It is a count, so give a whole number.

  • S∞−unS_\infty - u_n instead of S∞−SnS_\infty - S_n

    it scores no method mark.

  • Giving nn when the question asks for the value or the year.

    "Find the first negative term" wants the term itself. "In which year" wants a calendar year: if 2021 is u1u_1, then unu_n is the year 2020+n2020 + n, not 2021+n2021 + n.

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