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Find u₁ and d (or r)

Find u1u_1 and dd (or rr) from two facts

  • In 11 of 20 recent exams
  • 2% of the marks
  • Paper 1 or 2
  • 3 to 8 marks
How it is set in the exam

Paper 1 (no calculator) or Paper 2 (calculator), 3–8 marks. One of the two most common sequences questions (with Find n), usually part (a), followed by "hence find u20u_{20}", "find S15S_{15}" or a "show that".

Spot it in the exam
Exam phrases to spot (3)
  • “the third term is 7 and the tenth term is 35”

  • “find the first term and the common difference”

  • “find the common ratio”

In disguise (6)
  • one fact is a sum: "the sum of the first 10 terms is 185", or a sum to infinity
  • a relation instead of a value: "the fifth term is three times the second", "u5+u7=22u_5 + u_7 = 22" (one equation, not two)
  • two geometric terms an even number of steps apart: r2=9r^2 = 9 gives two sequences, and a later detail ("the fifth term is negative", "the terms alternate in sign") picks one
  • the two facts link an arithmetic and a geometric sequence (e.g. u2=v2u_2 = v_2, u4=v3u_4 = v_3)
  • the facts are logs: u1=ln⁡8u_1 = \ln 8 and u5=ln⁡128u_5 = \ln 128 give 4d=ln⁡164d = \ln 16, so d=ln⁡2d = \ln 2
  • one unknown trapped inside a sum formula on , which only the GDC can solve. If the condition is an inequality and the unknown is a whole number, the GDC gives the boundary value: take the whole number on the side where the inequality holds, and check its neighbours as in Find n
Looks like it, but isn't (3)
  • "the 2nd, 5th and 11th terms of an arithmetic sequence form a geometric sequence" is one condition on three terms: Three consecutive terms.
  • the facts only set the sequence up, and the question asks for nn (which term has a given value, or the least nn): Find n, with this type as its first step
  • the two facts are a sector's perimeter and area: Perimeter and area both given: find r and θ (the same structure: an equation each, eliminate, reject a root
Worked example

Two terms, then a sum

Paper 1 (no calculator)
Question

In an arithmetic sequence, u4=17u_4 = 17 and u11=52u_{11} = 52.
(a) Find the common difference and the first term. [5]
(b) Find the sum of the first 15 terms. [2]

Try it yourself first, then compare.

Now try one like it

Write your working on paper or on screen. Paper Zero marks it step by step, like the worked example, and shows where each mark went. Free, with no account.

A handwritten page as Paper Zero marks it: ticks at the two lines that earned a mark, a cross on line 3 where +7 was copied as −7, and a short note beside that line.123456f′(x) = 4x − 124x − 12 = 0, so x = 3f(3) = 2(3)² − 12(3) − 7= 18 − 36 − 7 = −25minimum at (3, −25)M1 ✓A1 ✓A1 ✗11The +7 became −7: 18 − 36 + 7 = −11.
See it move: Two facts pin the sequence down
  • Two unknowns, two facts: u1+3d=17u_1 + 3d = 17 and u1+10d=52u_1 + 10d = 52. Subtract: 7d=357d = 35, so d=5d = 5 and u1=17−3(5)=2u_1 = 17 - 3(5) = 2.
  • u4u_{4} is u1+3du_1 + 3d, not u1+4du_1 + 4d, and from u4u_{4} to u11u_{11} is 11−4=711 - 4 = 7 steps: the staircase has 7 risers, each dd high.
  • (b) S20=202(2(2)+19(5))=10×99=990S_{20} = \frac{20}{2}\left(2(2) + 19(5)\right) = 10 \times 99 = 990: the 2u1+(n−1)d2u_1 + (n - 1)d form, since u20u_{20} wasn't given.
  • A sum as the second fact is still linear in u1u_1 and dd: "the sum of the first ten terms is 185" means 102(2u1+9d)=185\frac{10}{2}(2u_1 + 9d) = 185, not u1+9d=185u_1 + 9d = 185. Divide by 5 before combining.
Steps
  1. Write each fact as an equation with the formula (unu_n, SnS_n or S∞S_\infty). Two unknowns need two equations.

  2. Both arithmetic:

    the equations are linear in u1u_1 and dd. Subtract to remove u1u_1. On : GDC: solve simultaneous linear equations.

  3. Both geometric:

    divide one equation by the other to cancel u1u_1. You get rk=r^k = number.

  4. If kk is even and rk>0r^k > 0, rr has two values (±\pm); if kk is odd, one. Keep both unless something in the question rules one out.

  5. One fact of each type

    (linked sequences): make dd the subject and substitute. A quadratic in rr follows, and r=1r = 1 usually has to be rejected (it makes d=0d = 0).

  6. Substitute back to find u1u_1, then answer what was actually asked (a later term, a sum, or a "show that").

Common mistakes
  • Reading S10S_{10} as u10u_{10}

    "the sum of the first ten terms is 185" means 102(2u1+9d)=185\frac{10}{2}(2u_1 + 9d) = 185, not u1+9d=185u_1 + 9d = 185.

  • Premature rounding

    in Example 1.4, using r=1.09r = 1.09 gives u10≈434u_{10} \approx 434, not 425425. Keep the full value in the calculator (keep full-accuracy values).

  • Losing a root

    r2=9r^2 = 9 gives r=±3r = \pm 3. Only reject one if the question gives a reason.

More mistakes (3)
  • Subtracting geometric equations.

    Geometric facts are products, so divide them. Subtracting u1r3−u1ru_1 r^3 - u_1 r gets you nowhere.

  • Using nn instead of n−1n - 1

    u4=u1+3du_4 = u_1 + 3d, not u1+4du_1 + 4d.

  • Keeping r=1r = 1 for linked sequences

    it makes d=0d = 0, so both sequences are constant. Reject it and say why.

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