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Probability distribution tables

Find the unknown, then E(X) and probabilities

  • In 14 of 20 recent exams
  • 2% of the marks
  • Paper 1 or 2
  • 1 to 5 marks
How it is set in the exam

Paper 1 (no calculator) and Paper 2 (calculator) (6 and 8 of its 14 exam versions), 1–5 marks per part, usually 2. Half the time it is in a Section A question of 5–6 marks, usually most or all of it, and half the time part of a Section B question, usually the opening parts. Very common (14 of 20 exam versions), and it is the step the other two types in this guide end with.

Spot it in the exam
Exam phrases to spot (6)
  • “find the value of kk”

  • “find E(X)\mathrm{E}(X)”

  • “find P(X>c)\mathrm{P}(X > c)”

  • “given that E(X)=…\mathrm{E}(X) = \ldots, find pp and qq”

  • “find the possible values of pp”

  • “show that …k2…=0\ldots k^2 \ldots = 0”

In disguise (4)
  • a frequency table of data, and an "expected" value per person: the relative frequencies are the probabilities
  • P(X=x)\mathrm{P}(X = x) given as a formula in xx: write out the table first
  • the probabilities follow a pattern (an arithmetic or geometric sequence): they still add up to 11 (Where it hides)
  • one value of XX is unknown and E(X)\mathrm{E}(X) is given: the E(X)\mathrm{E}(X) equation is linear in it
Variants (3)
  • the table: multiples of kk; a quadratic in kk; powers of kk (, GDC); a formula in xx; a frequency table; a table built in an earlier part from an experiment
  • given as well: E(X)\mathrm{E}(X) (two unknowns, or an unknown value of XX)
  • asked: kk, E(X)\mathrm{E}(X), the probability of a range, the mode, the possible values of a parameter, the range of E(X)\mathrm{E}(X)
Looks like it, but isn't (4)
  • kk is in Venn regions, tree branches or a two-way table of events, with a fact such as independence: Probabilities in terms of an unknown
  • the entries must first be built by listing outcomes: Build the distribution from the experiment
  • unknown frequencies of a data set, with its mean: Work backwards from the mean or median (the same two equations, with nn in place of 11
  • "given that", with both events ranges of XX: Given that X is in a range
Worked example

Linear in k, a cut-off between two values, then E(X)

Paper 1 (no calculator)
Question

The random variable XX has this probability distribution.

xxP(X=x)\mathrm{P}(X = x)
000.050.05
113k3k
220.350.35
332k2k
44kk

(a) Find the value of kk. [2]
(b) Find P(X>2.5)\mathrm{P}(X > 2.5). [2]
(c) Find E(X)\mathrm{E}(X). [2]

Try it yourself first, then compare.

Now try one like it

Write your working on paper or on screen. Paper Zero marks it step by step, like the worked example, and shows where each mark went. Free, with no account.

A handwritten page as Paper Zero marks it: ticks at the two lines that earned a mark, a cross on line 3 where +7 was copied as −7, and a short note beside that line.123456f′(x) = 4x − 124x − 12 = 0, so x = 3f(3) = 2(3)² − 12(3) − 7= 18 − 36 − 7 = −25minimum at (3, −25)M1 ✓A1 ✓A1 ✗11The +7 became −7: 18 − 36 + 7 = −11.
Which method?

The equation from "total =1= 1" (and from E(X)\mathrm{E}(X), if it is given) decides the route.

The equationSolve by
linear in kkrearranging
quadratic in kkfactorising on ; on , solve a polynomial equation. Then test each root in every entry
powers of kk, with a second unknowneliminate the second unknown, then solve the polynomial equation; or write the second unknown from each equation and intersect the two graphs
two unknowns, both linear (total 11 and E(X)\mathrm{E}(X))simultaneous equations, by hand or on the GDC
no equation: the total is 11 whatever the parameter is0≤0 \le each entry ≤1\le 1: one interval per entry, then their overlap
Steps
  1. Total =1= 1:

    add every entry, including the one at x=0x = 0, and set the sum equal to 11. If E(X)\mathrm{E}(X) is given, write ∑x P(X=x)=E(X)\sum x\,\mathrm{P}(X = x) = \mathrm{E}(X) as a second equation.

  2. Solve

    (the table above). Then test every root in every entry: a root is valid only if all the entries lie between 00 and 11. Reject the others, naming the entry that fails, and only after all the roots have been found.

  3. A probability of a range:

    translate the words into values of XX (Inequality words), then add those entries, or use the complement. The mode is the value with the largest entry.

  4. E(X)\mathrm{E}(X):

    write the sum with every term, then its value. Check that it lies between the smallest and the largest value of XX.

  5. The possible values of a parameter:

    write 0≤entry≤10 \le \text{entry} \le 1 for every entry containing it, and take the overlap. When every entry is linear in the parameter, so is E(X)\mathrm{E}(X), and its least and greatest values come from the ends of that interval.

Common mistakes
  • Checking a given value instead of solving.

    In a "show that", substituting the given kk (or pp and qq) to check the total earns the method mark at most: set up the equations and solve them forwards.

  • Rejecting only negative roots.

    A positive root can still make an entry negative or bigger than 11 (k=0.5k = 0.5 in Example 1.2). Test every entry.

  • Leaving the rejected root in

    (), or rejecting it with no reason (). When the root is itself an entry, "a probability can't be negative" is enough. When it isn't, name the entry that fails: P(X=2)=0.4−0.5<0\mathrm{P}(X = 2) = 0.4 - 0.5 < 0. The reason () only counts after both roots have been found.

More mistakes (8)
  • E(X)\mathrm{E}(X) for both roots

    . Work out E(X)\mathrm{E}(X) with the valid value only.

  • Leaving out P(X=0)\mathrm{P}(X = 0)

    from the total: it adds nothing to E(X)\mathrm{E}(X), but it is part of the 11.

  • Dividing E(X)\mathrm{E}(X) by the number of values,

    as if it were the mean of the xx values: the probabilities already do the averaging.

  • Translating the words wrongly

    "fewer than 33" is X≤2X \le 2, and "more than 2.52.5" is X≥3X \ge 3 (Inequality words).

  • Giving the probability as the mode.

    The mode is a value of XX.

  • The ends of the range of E(X)\mathrm{E}(X) the wrong way round

    when E(X)\mathrm{E}(X) decreases as the parameter increases: 1≤E(X)≤2.21 \le \mathrm{E}(X) \le 2.2, not 2.2≤E(X)≤12.2 \le \mathrm{E}(X) \le 1.

  • Rounding kk on

    before using it again: keep the stored value, and give answers to 3 s.f.

  • Carrying on with an invalid kk

    later parts earn follow-through marks only when your kk makes every entry a valid probability (one markscheme needed 0<k<10 < k < 1, and a probability from the table below 11). If an entry comes out negative or above 11, find the slip before going on.

Next typeExpected value in context