Greatest or least values in motion
Greatest or least velocity, speed, acceleration or displacement on an interval
- In 9 of 20 recent exams
- Paper 1 or 2
- 1 to 5 marks
How it is set in the exam
Paper 1 (no calculator) (3 exam versions) and Paper 2 (calculator) (6), 1–5 marks per part, often two or three linked parts. Common (9 of 20 exam versions). In 4 of them the answer is at an end of the interval, and checking the end has a mark of its own.
Exam phrases to spot (4)
“find the maximum velocity”
“find the greatest speed of the particle for 0≤t≤5”
“find the minimum acceleration”
“find the maximum displacement”
In disguise (5)
- "the maximum distance of the particle from O": the greatest ∣s∣, so a negative s can win
- the greatest acceleration when a(t) is one sine or cosine with no constant term, such as a=−18sin3t (from s=1+2sin3t): its amplitude, 18 m s−2, if a peak of a is in the interval (an end counts). Otherwise use dtda=0 and the ends: with a constant term (a=2+3cost peaks at 5, not 3), a growing factor (as in Example 2.2) or no peak inside the interval, there is no shortcut
- s(t) is given and the greatest velocity is asked for: the greatest gradient of s, which can be at the start
- "the least speed": 0 whenever v=0 somewhere in the interval
- the greatest distance between two particles: the gap ∣sB−sA∣, with candidates where vA=vB, and the ends
Looks like it, but isn't (4)
- "when is the acceleration zero?", with no greatest or least asked for: Velocity and acceleration: at rest, direction, speed
- the greatest rate of change of a quantity that isn't a motion (a population, a volume): Concavity and points of inflexion
- the greatest value of a quantity that isn't a motion, on a given interval: Stationary points: find them and justify their nature, comparing the ends
- the velocity is a sinusoid and no derivative is asked for: the times of its extremes, and how many there are, come from the period (Read a sinusoid's features)
The greatest speed is at the start
A particle moves in a straight line with velocity v(t)=2t3−21t2+60t−30 m s−1, for 0≤t≤6.
(a) Find the acceleration a(t). [2]
(b) Find the greatest velocity of the particle. [4]
(c) Find the greatest speed of the particle. [3]
Try it yourself first, then compare.
Now try one like it
Write your working on paper or on screen. Paper Zero marks it step by step, like the worked example, and shows where each mark went. Free, with no account.
- a(t)=v′(t)=6t2−42t+60=6(t−2)(t−5), so a=0 at t=2 and t=5.
- The candidates on 0≤t≤6: v(0)=−30 (an end), v(2)=22 (a=0), v(5)=−5 (a=0), v(6)=6 (an end). Where a=0 outside the interval doesn't count; the ends always do.
- The greatest velocity is 22 m s−1, at t=2 (a=0); the least is −30, at t=0 (an end).
- Speed is ∣v∣: the sizes 30, 22, 5, 6. The greatest speed is 30 m s−1, at t=0 (an end). v passes through 0 on the way, so the least speed is 0.
- (b) The greatest velocity is 22 m s−1, at t=2. (c) The greatest speed is 30 m s−1, at the start: a large negative velocity is the least velocity but can be the greatest speed.
- 1
Name the quantity.
It decides both the candidates and the comparison:
- velocity v
- Candidates inside the interval
- a=0
- Also
- both ends
- Compare
- values, with their signs
- speed ∣v∣
- Candidates inside the interval
- a=0
- Also
- both ends
- Compare
- sizes: a negative v can win. The least speed is 0 whenever v=0 somewhere in the interval
- acceleration a
- Candidates inside the interval
- dtda=0 (for one sine or cosine with no constant term: its amplitude, if a peak is in the interval)
- Also
- both ends
- Compare
- values
- displacement s
- Candidates inside the interval
- v=0: where v changes from + to − (greatest) or from − to + (least)
- Also
- both ends
- Compare
- values
- distance from O, ∣s∣
- Candidates inside the interval
- v=0
- Also
- both ends
- Compare
- sizes: a negative s can win. The least distance from O is 0 whenever s=0 somewhere in the interval
Greatest or least … Candidates inside the interval Also Compare velocity v a=0 both ends values, with their signs speed ∣v∣ a=0 both ends sizes: a negative v can win. The least speed is 0 whenever v=0 somewhere in the interval acceleration a dtda=0 (for one sine or cosine with no constant term: its amplitude, if a peak is in the interval) both ends values displacement s v=0: where v changes from + to − (greatest) or from − to + (least) both ends values distance from O, ∣s∣ v=0 both ends sizes: a negative s can win. The least distance from O is 0 whenever s=0 somewhere in the interval - 2
Find the candidates:
by solving; with maximum or minimum of a graph, on the graph of the quantity itself. If that quantity is a derivative of what you were given (v from s, or a from v), draw it with graph of the derivative, or differentiate by hand first.
- 3
Values:
substitute (), or read them from the GDC (). A displacement at a candidate time t∗ is s(t∗)=s(0)+∫0t∗vdt (definite integral), with t∗ at full accuracy (keep full-accuracy values).
- 4
Compare every candidate, the ends included.
No nature test is needed: the comparison decides.
- 5
Answer:
the value with its units, and the time if it is asked for.
Comparing the turning points only
the end of the interval can win, and checking it has its own mark (Examples 2.1 and 2.2).
The greatest speed from the greatest velocity
a large negative velocity is a large speed.
The least speed as the least velocity
the least speed is 0 whenever v=0 somewhere in the interval.
More mistakes (3)
The greatest displacement where v is greatest
it is where v=0 (changing from + to −), or at an end.
Displacement for distance from O
the distance from O is ∣s∣ (Example 2.3(c)).
Degree mode
with trig: ().