Paper ZeroSign in

Greatest or least values in motion

Greatest or least velocity, speed, acceleration or displacement on an interval

  • In 9 of 20 recent exams
  • Paper 1 or 2
  • 1 to 5 marks
How it is set in the exam

Paper 1 (no calculator) (3 exam versions) and Paper 2 (calculator) (6), 1–5 marks per part, often two or three linked parts. Common (9 of 20 exam versions). In 4 of them the answer is at an end of the interval, and checking the end has a mark of its own.

Spot it in the exam
Exam phrases to spot (4)
  • “find the maximum velocity”

  • “find the greatest speed of the particle for 0≤t≤50 \le t \le 5”

  • “find the minimum acceleration”

  • “find the maximum displacement”

In disguise (5)
  • "the maximum distance of the particle from OO": the greatest ∣s∣\lvert s \rvert, so a negative ss can win
  • the greatest acceleration when a(t)a(t) is one sine or cosine with no constant term, such as a=−18sin⁡3ta = -18\sin 3t (from s=1+2sin⁡3ts = 1 + 2\sin 3t): its amplitude, 1818 m s−2^{-2}, if a peak of aa is in the interval (an end counts). Otherwise use dadt=0\frac{da}{dt} = 0 and the ends: with a constant term (a=2+3cos⁡ta = 2 + 3\cos t peaks at 55, not 33), a growing factor (as in Example 2.2) or no peak inside the interval, there is no shortcut
  • s(t)s(t) is given and the greatest velocity is asked for: the greatest gradient of ss, which can be at the start
  • "the least speed": 00 whenever v=0v = 0 somewhere in the interval
  • the greatest distance between two particles: the gap ∣sB−sA∣\lvert s_B - s_A \rvert, with candidates where vA=vBv_A = v_B, and the ends
Looks like it, but isn't (4)
  • "when is the acceleration zero?", with no greatest or least asked for: Velocity and acceleration: at rest, direction, speed
  • the greatest rate of change of a quantity that isn't a motion (a population, a volume): Concavity and points of inflexion
  • the greatest value of a quantity that isn't a motion, on a given interval: Stationary points: find them and justify their nature, comparing the ends
  • the velocity is a sinusoid and no derivative is asked for: the times of its extremes, and how many there are, come from the period (Read a sinusoid's features)
Worked example

The greatest speed is at the start

Paper 1 (no calculator)
Question

A particle moves in a straight line with velocity v(t)=2t3−21t2+60t−30v(t) = 2t^3 - 21t^2 + 60t - 30 m s−1^{-1}, for 0≤t≤60 \le t \le 6.
(a) Find the acceleration a(t)a(t). [2]
(b) Find the greatest velocity of the particle. [4]
(c) Find the greatest speed of the particle. [3]

Try it yourself first, then compare.

Now try one like it

Write your working on paper or on screen. Paper Zero marks it step by step, like the worked example, and shows where each mark went. Free, with no account.

A handwritten page as Paper Zero marks it: ticks at the two lines that earned a mark, a cross on line 3 where +7 was copied as −7, and a short note beside that line.123456f′(x) = 4x − 124x − 12 = 0, so x = 3f(3) = 2(3)² − 12(3) − 7= 18 − 36 − 7 = −25minimum at (3, −25)M1 ✓A1 ✓A1 ✗11The +7 became −7: 18 − 36 + 7 = −11.
See it move: The ends are candidates too
  • a(t)=v′(t)=6t2−42t+60=6(t−2)(t−5)a(t) = v'(t) = 6t^{2} - 42t + 60 = 6(t - 2)(t - 5), so a=0a = 0 at t=2t = 2 and t=5t = 5.
  • The candidates on 0≤t≤60 \le t \le 6: v(0)=−30v(0) = -30 (an end), v(2)=22v(2) = 22 (a=0a = 0), v(5)=−5v(5) = -5 (a=0a = 0), v(6)=6v(6) = 6 (an end). Where a=0a = 0 outside the interval doesn't count; the ends always do.
  • The greatest velocity is 2222 m s−1^{-1}, at t=2t = 2 (a=0a = 0); the least is −30-30, at t=0t = 0 (an end).
  • Speed is ∣v∣\lvert v \rvert: the sizes 3030, 2222, 55, 66. The greatest speed is 3030 m s−1^{-1}, at t=0t = 0 (an end). vv passes through 0 on the way, so the least speed is 0.
  • (b) The greatest velocity is 2222 m s−1^{-1}, at t=2t = 2. (c) The greatest speed is 3030 m s−1^{-1}, at the start: a large negative velocity is the least velocity but can be the greatest speed.
Steps
  1. Name the quantity.

    It decides both the candidates and the comparison:

    • velocity vv
      Candidates inside the interval
      a=0a = 0
      Also
      both ends
      Compare
      values, with their signs
    • speed ∣v∣\lvert v \rvert
      Candidates inside the interval
      a=0a = 0
      Also
      both ends
      Compare
      sizes: a negative vv can win. The least speed is 00 whenever v=0v = 0 somewhere in the interval
    • acceleration aa
      Candidates inside the interval
      dadt=0\frac{da}{dt} = 0 (for one sine or cosine with no constant term: its amplitude, if a peak is in the interval)
      Also
      both ends
      Compare
      values
    • displacement ss
      Candidates inside the interval
      v=0v = 0: where vv changes from ++ to −- (greatest) or from −- to ++ (least)
      Also
      both ends
      Compare
      values
    • distance from OO, ∣s∣\lvert s \rvert
      Candidates inside the interval
      v=0v = 0
      Also
      both ends
      Compare
      sizes: a negative ss can win. The least distance from OO is 00 whenever s=0s = 0 somewhere in the interval
  2. Find the candidates:

    by solving; with maximum or minimum of a graph, on the graph of the quantity itself. If that quantity is a derivative of what you were given (vv from ss, or aa from vv), draw it with graph of the derivative, or differentiate by hand first.

  3. Values:

    substitute (), or read them from the GDC (). A displacement at a candidate time t∗t^* is s(t∗)=s(0)+∫0t∗v dts(t^*) = s(0) + \int_0^{t^*} v\,dt (definite integral), with t∗t^* at full accuracy (keep full-accuracy values).

  4. Compare every candidate, the ends included.

    No nature test is needed: the comparison decides.

  5. Answer:

    the value with its units, and the time if it is asked for.

Common mistakes
  • Comparing the turning points only

    the end of the interval can win, and checking it has its own mark (Examples 2.1 and 2.2).

  • The greatest speed from the greatest velocity

    a large negative velocity is a large speed.

  • The least speed as the least velocity

    the least speed is 00 whenever v=0v = 0 somewhere in the interval.

More mistakes (3)
  • The greatest displacement where vv is greatest

    it is where v=0v = 0 (changing from ++ to −-), or at an end.

  • Displacement for distance from OO

    the distance from OO is ∣s∣\lvert s \rvert (Example 2.3(c)).

  • Degree mode

    with trig: ().

Next typeOptimisation